-0.03x^2+1.53x=0

Solution for -0.03x^2+1.53x=0 equation:

-0.03x^2+1.53x=0

a = -0.03; b = 1.53; c = 0;
Δ = b2-4ac
Δ = 1.532-4·(-0.03)·0
Δ = 2.3409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.53)-\sqrt{2.3409}}{2*-0.03}=\frac{-1.53-\sqrt{2.3409}}{-0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.53)+\sqrt{2.3409}}{2*-0.03}=\frac{-1.53+\sqrt{2.3409}}{-0.06}
$